If tan^-1 (√3) + cot^-1 x = π/2, then find x.
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heya!!!
Cot^-1( x ) = π / 2 - π / 3
cot^-1 ( x ) = π / 6
x = cot( π / 6 )
x = √3
Have a great future ahead.
Cot^-1( x ) = π / 2 - π / 3
cot^-1 ( x ) = π / 6
x = cot( π / 6 )
x = √3
Have a great future ahead.
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