Question

If tanθ=1/√3 then the value of cos2θ=​

Answer 1

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$\tan(θ) = \frac{1}{ \sqrt{3} } \\ to \: find \: = \cos(2θ) \\ \cos(2θ) = \frac{1 - { \tan(θ) }^{2} }{1 + { \tan(θ) }^{2} } \\ = \frac{1 - { (\frac{1}{ \sqrt{3} } })^{2} }{1 +( { \frac{1}{ \sqrt{3} } })^{2} } \\ = \frac{1 - \frac{1}{3} }{1 + \frac{1}{3} } \\ = \frac{ \frac{3 - 1}{3} }{ \frac{3 + 1}{3} } \\ = \frac{ \frac{2}{3} }{ \frac{4}{3} } \\ = \frac{1}{2}$

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Answer 2

Answer:

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