IF tan^-1(a/x) + tan^-1(b/x) = π/2 ,then x =?
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0
Answer:
What did youvll written....ghr
Step-by-step explanation:
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Answered by
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Step-by-step explanation:
tan^-1[(a/x+b/x)/1-(a/x)(b/x)] = π/2
tan^-1[ (ab/x)/1-(ab/x^2)] = π/2
(ab/x)/1-ab/x^2 = tanπ/2
1-(ab/x^2) = 0
1 = ab/x^2
x^2= ab
x=√ab
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