Math, asked by jollynag549, 5 months ago

If tan(α – β) = 1 and sec(α + β) = 2/3, find the smallest positive values α and β.

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Answered by ratilalparmar011

0

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If If tan(α – β) = 1 and sec(α + β) = 2/3, find the smallest positive values α and β. (α – β) = 1 and sec(α + β) = 2/3, find the smallest positive values α and β. If tan(α – β) = 1 and sec(α + β) = 2/3, find the smallest positive valuttttttes α and β.

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