If tan θ = 1, find the value of 5cot^2 + sin^2 − 1
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Answer:
If 5cotθ=4 then the value of (
sinθ+2cosθ
5sinθ−3cosθ
) is :
Answer
(
sinθ+2cosθ
5sinθ−3cosθ
)
Dividing numerator and denominator by sinθ we get:
=
1+2cotθ
5−3cotθ
=
1+2×
5
4
5−3×
5
4
=1
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