If tan θ₁= kcot θ₂, then cos (θ₁-θ₂) /cos(θ₁+θ₂) =?
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tan θ₁= kcot θ₂, then cos (θ₁-θ₂) /cos(θ₁+θ₂) =
1+K/1-K
[we have to put sinθ₁sinθ₂ = Kcosθ₁cosθ₂]
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