Question

If tanθ=1 then, find the values of sinθ+ cosθ/secθ+cosecθ

Answer 1

$\bf{Given,}$ tanθ = 1
we know, tanθ = tan45° = 1
so, θ = 45°
∴ sin45° = 1/√2 , cos45° = 1/√2
sec45° = √2 and cosec45° = √2

now, (sinθ + cosθ)/(secθ + cosecθ)
= (1/√2 + 1/√2)/(√2 + √2)
= (2/√2)/(2√2)
= (√2)/(2√2)
= 1/2

Hence, $\bf{\frac{sin\theta+cos\theta}{sec\theta+cosec\theta}=\frac{1}{2}}$

Answer 2

Answer:

Ans -2/4=1/2

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