if tan^-1(x-1/x+2)+tan^-1(x+1/x+2)=pi/4
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Given that, a + b = 1
Taking cube of both sides, we get
(a + b)3 = 1
⇒ a3 + b3 + 3ab(a + b) = 1
⇒ a3 + b3 + 3ab = 1Short Trick:
Here, One equation and two variable, so a and b can have infinite value.
let suppose that b = 0
⇒ a = 1
So, a3 + b3 + 3ab
⇒ 13 + 0 + 0 = 1
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