Question

if tan=15/8 find the value of sin theta

Answer 1

Here is your ans
tan theta= 15/8
= perpendicular/base
sin theta= perpendicular/hypotenuse
so here hypotenuse^2= (15)^2+(8)^2
= 225+64
=√289=17
hence sin theta= 15/17
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Answer 2

Hey there!

Solution:


$tan = \frac{15}{8}\\ \\ tan = \frac{P}{B} \\ \\ Therefore, \\ \\ P = 15 , B = 8 \\ \\ Where\: P = Perpendicular , B = Base\\ \\ Now\: Using\: Pythagoras Theorem:\\ \\ H^{2} =B^{2} + P^{2}\\ \\ H^{2} = (8)^{2} +\ (15)^{2} \\ \\ H^{2} = 64 + 225\\ \\ H^{2} = 289\\ \\ H^{2} = (17)^{2}\\ \\ H = 17\\ \\ We\: know\: that :\\ \\ sin = \frac{P}{H}\\ \\Where \:H \:is\: Hypotenuse\\ \\ Sin = \frac{15}{17}$

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