If tan-1x=3/4 then cos-1x value
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Given,
Tan(x)=3/4=(opposite side)/(adjacent side)
We know that, Cos(x)=(adjacent side)/(Hypotenuse)
From pythagoras theorem,
(opposite side)^2+(adjacent side)^2=(Hypotenuse)^2
(3)^2+(4)^2=9+16=25=(5)^2
that implies Hypotenuse =5
Therefore, cos(x)=adj/hyp=4/5.
Tan(x)=3/4=(opposite side)/(adjacent side)
We know that, Cos(x)=(adjacent side)/(Hypotenuse)
From pythagoras theorem,
(opposite side)^2+(adjacent side)^2=(Hypotenuse)^2
(3)^2+(4)^2=9+16=25=(5)^2
that implies Hypotenuse =5
Therefore, cos(x)=adj/hyp=4/5.
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