Question

If tan^-1x + tan^-1y= π^2 then dy/dx=​

Answer 1

Answer:

Let tan−1x+tan−1y=π4

⇒tan−1(x+y1−xy)=π4

(Usingtan−1A+tan−1B=tan−1(A+B1−AB))

⇒x+y1−xy=tanπ4=1

⇒x+y=1−xy

⇒x+y+xy=1

Step-by-step explanation: