Question

if tan=2/3 and tan y=3/4 find the value of tan(x+y).

Answer 1

Answer:

If tan x = 2/3, and tan y = 3/4, what is the value of tan (x + y)?

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If tan x=2/3 and tan y=3/4, what is the value of tan(x+y)?

The formula is

tan(x+y)=tanx+tany1−tanxtany.

tanx=23, tany=34⟹

tan(x+y)=23+341−23×34

=812+9121−612

=(1712)(612)

=176

or

tan x = 2/3 and tan y = 3/4.

Now, tan (x+y) = [tan x + tan y]/[1 - tan x*tan y]

= [(2/3) + (3/4)]/[1 - (2/3)*(3/4)]

= [8+9]/12*[1 - (2/3)*(3/4)]

= 17/12*(1/2)

= 17/6

Answer: tan (x+y) = 17/6.

Answer 2

Step-by-step explanation:

AS WE KNOW

$\tan(x + y) = \frac{ \tan x \: + \tan(y) }{1 - \tan \: x \: \tan(y) }$

PUT THE VALUES OF TAN X AND TAN Y

U WILL GET

(2/3 + 3/4)/1-(2/3)(3/4)

WHICH IS EQUAL TO

17/6

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