Question

if tan^2(3A+15)°-1=0 then find the value of A that satisfy this condition

Answer 1

Here is your answer :

Given,

=> tan² ( 3A + 15 )° - 1 = 0

Adding 1 to both sides,

=> tan² ( 3A + 15 )° - 1 + 1 = 0 + 1

=> tan² ( 3A + 15 )° = 1 --------- ( 1 )

We know that,

=> tan 45° = 1

Squaring both sides,

=> ( tan 45° )² = 1²

=> tan² 45° = 1 ------------ ( 2 )

From ( 1 ) and ( 2 ),

=> tan²( 3A + 15 )° = tan² 45°

As the trigonometric ratios are equal, so angle will be also equal.

=> ( 3A + 15 )° = 45°

=> 3A + 15 = 45

=> 3A = 45 - 15

=> 3A = 30

=> A = 30 ÷ 3

•°• A = 10.

Hope it helps !!