Question

If tan^ 2 45° -cos^ 2 30° =x.sin 45° cos 45° then find the value of x. ​

Answer 1

Answer:

bro its Veryy Easy

Step-by-step explanation:

go and learn the all of its degree

Answer 2

$\sf\tan^{2} 45°\cos^{2} 30° = \red x \: \sin45° \cos45° \\ \\ \sf (1)^{2}\: \left(\frac{ \sqrt{3} }{2}\right)^{2} = \red{x} \: \left(\frac{1}{ \sqrt{2}}\right)\left(\frac{1}{ \sqrt{2}}\right) \\ \\ \sf 1 \: \times \: \frac{3}{4} \: = \red{x}\: \: \: \frac{ \cancel{\sqrt{2}}}{ \cancel{\sqrt{2}}} \\ \\ {\underline{\boxed{\bf{{\red{x}} \: = \: \frac{3}{4}}}}}$