If tan 20° = lamda, then show that
tan 160° - tan 110°
1 + tan 160°.tan 110°
1-lamda2
2lamda
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Answer:
Given tan20
∘
=λ
tan40
∘
=tan2(20
∘
)=
1−tan
2
20
∘
2tan20
∘
=
1−λ
2
2λ
LHS=
1+tan160
∘
tan110
∘
tan160
∘
−tan110
∘
=tan(160
∘
−110
∘
)=tan50
∘
=tan(90
∘
−40
∘
)=cot40
∘
=
tan40
∘
1
=
2λ
1−λ
2
=RHS
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