Question

if tan 2A = 2 cot (a + 18) where to a and a + 18 are acute angles find the value of a​

Answer 1

Answer:

Given tan2A=cot(A−18

0

)

⇒cot(90−2A)=cot(A−18

0

)[∵tanθ=cot(90−θ)]

Comparing angles we get

90−2A=A−18

⇒90+18=A+2A

⇒3A=108

⇒A=

3

108

⇒A=36

∘