Question

If Tan 2A = cos (A-18) where 2A is an acute angle,find the value of A

Answer 1

Heya...!!!!

I think some typing mistake
It should be cot(A - 18) not cos(A - 18)

tan2A = cos(A - 18)
[ tan∅ = cot(90 - ∅)]

=> cot(90 - 2A) = cot(A - 18)

=> 90 - 2A = A - 18

=> 2A + A = 90 + 18

=> 3A = 108

=> A = 108/3

=> A = 36

Answer 2

HELLO DEAR,

we know that:-

cottheta = tan(90 - theta)

tan2A = tan[90 - (A - 18)]

=> 2A = 90 - A + 18

=> 3A = 108

=> A = 108/3

=> A = 36

I HOPE ITS HELP YOU DEAR,
THANKS