if tan 2A=cos(A-18°),what 2A is an acute angle,find the value of A
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Answered by
1
I think you question is wrong .....
There might be cot instead of cos
tan 2A= cot(A-18°)
cot(90°-2A)=cot(A-18°)
90°-2A = A-18°
2A+A = 90°+18°
3A = 108°
A = 36°
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Hope this helps you... ....
There might be cot instead of cos
tan 2A= cot(A-18°)
cot(90°-2A)=cot(A-18°)
90°-2A = A-18°
2A+A = 90°+18°
3A = 108°
A = 36°
----------------------------
Hope this helps you... ....
Harshbhavna:
Plz mark me as brainliest-------
Answered by
0
if it is cotA instead of cosA
tan2A =cot(A-18°)
cot (90-2A)=cot (A-18)
cot get cancelled,
90-2A= A-18
90+18 = A +2A
108 =3A
A= 36
2A =2×36
=72
tan2A =cot(A-18°)
cot (90-2A)=cot (A-18)
cot get cancelled,
90-2A= A-18
90+18 = A +2A
108 =3A
A= 36
2A =2×36
=72
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