if tan 2A= cot (A-18) degree where 2A is an acute angle then find the value of A
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Answered by
15
Answer:
Step-by-step explanation:
Tan 2A = cot(90 - 2A)
Cot(90 - 2A) = cot ( A - 18)
90 - 2A = A - 18
-2A - A = - 18 - 90
-3A = -108
A = 36
cuteprincess85:
A=36 kase aagya
Answered by
6
Solution:
It is given that tan2A=cot(A−18°)
⇒tan2A=cot(90° −(108° −A))
⇒tan2A=tan(108° −A)
{°•° cot(90° −A)=tan(A)}
⇒2A=108° −A
⇒3A=108°
⇒A=108°/3 =36°
Thanks ☺
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