Question

if tan 2a = cot (a-18) where 2a is an acute angle find the value of a
.....please do it......​

Answer 1

Answer:

Step-by-step explanation:

tan 2A = Cot  ( A - 18 Degree)

cot ( 90- 2A) = cot ( A -18)

COMPARING ANGLES

90- 2A = A - 18

90 + 18 = A + 2A

108 = 3A

108 / 3 = A

A= 36

THUS , A = 36.

Answer 2

GIVEN THAT

=>TAN 2A = COT (A-18°)

=>COT ( 90°-2A) = COT (A-18°)

=>90°-2A = A - 18°

=>90°+18 = A + 2A

=> 3A = 108

=> A = 108 / 3

= 36

.....HENCE THE VALUE OF A IS 36°......