Question

If tan 2a = cot(a-18), where 2a is an acute angle, find the value of a



My answer is:
Tan2a=cot(90-a-18)
2a=72-a
3a=72
a=24
?

Answer 1

Answer:

a=36

Step-by-step explanation:

tan2a=cot(a-18)

cot(90-2a)=cot(a-18)

90-2a=a-18

108=3a

a=36

Remember that both angles have to be complementary in order to be equal

therefore tan2(36)=cot(36-18)

tan72=cot18

72+18=90

Answer 2

Step-by-step explanation:

$tan2a = cot(a - 18) \\ tan2a = tan( {90} - a + 18) \\ 2a = 108 - a \\ 3a = 108 \\ a = {36}^{0} \\ \\ hope \: it \: will \: help \: you.$