if tan 2A=cot(A-18)where 2A is an acute angle find the value of A
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Answered by
9
cot(90-2A)=cot(A-18)
comparing both side we get
90-2A=A-18
90+18=2A+A
108=3A
A=36
Hope u understand
comparing both side we get
90-2A=A-18
90+18=2A+A
108=3A
A=36
Hope u understand
Answered by
4
Tan(2A) can be written as cot(90-2A)
Therefore
90-2A=A-18
3A=108
A=36
Therefore
90-2A=A-18
3A=108
A=36
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