If tan 2A=cot(A-18),where 2A is an acute angle, find the value of A.
Answers
Answered by
4
Given that,
Tan2A=Cot(A-18*)
COT(90*-2A)=COT(A-18*) ((BY USING IDENTITY))
COT AND COT GOT CANCELLED BUT WE DONT HAVE TO SHOW IT ON THE PAPER OR IN THE EXAM
NOW LEFT,
90*-2A=A-18*
90*+18*=A+2A
THERE FORE,
A=36*
Tan2A=Cot(A-18*)
COT(90*-2A)=COT(A-18*) ((BY USING IDENTITY))
COT AND COT GOT CANCELLED BUT WE DONT HAVE TO SHOW IT ON THE PAPER OR IN THE EXAM
NOW LEFT,
90*-2A=A-18*
90*+18*=A+2A
THERE FORE,
A=36*
Answered by
5
Ram Ram bhai .....✌☺
We have ,
Tan 2A = Cot (A-18°)
So,
Tan 2A= Tan (90°-18°)
From above we conclude that........
3A= 108°
A= 108/3
A=36°
Hope it Helps U Dear
We have ,
Tan 2A = Cot (A-18°)
So,
Tan 2A= Tan (90°-18°)
From above we conclude that........
3A= 108°
A= 108/3
A=36°
Hope it Helps U Dear
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