if tan 2A=cot ( A-18°),where 2A is an acute angle,find the value of A???easy method
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==> tan 2A = cot ( A - 18 )
==> tan 2A = tan ( 90 - ( A - 18) )
==> 2A = 90 - A + 18
==> 3A = 108
==> A = 36
Value of A is 36
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