Question

if tan 2A =cot ( A-18°),where 2A is an acute angle. find the value of A

Answer 1

Tan2A=cot(90°-2A)

Cot(90°-2A) =cot(A-18°)

90°+18=3A°

108°=3A

A=108°/3

A=36° @rajukumar

Answer 2

Given : tan 2A = cot(A – 18)°

cot(90 – 2A) = cot(A – 18)°

90 – 2A = A – 18

– 2A – A = – 18 – 90

– 3A = – 108

A = $\bf\huge\frac{-108}{-3}$

A = 36