If tan 2a = cot (a-180) where 2a is an acute angle. Find the value of a
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Solution:
( itz 18°, not 180 )✌
It is given that tan2A=cot(A−18°)
⇒tan2A=cot(90° −(108° −A))
⇒tan2A=tan(108° −A)
{°•° cot(90° −A)=tan(A)}
⇒2A=108° −A
⇒3A=108°
⇒A=108°/3 =36°
Thanks ☺
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