If tan 2a = cot (a - 18â°), where 2a is an acute angle, find the value of a.
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Answered by
0
Answer:
Given tan 2a = cot (a - 18 )
To find = a
Step-by-step explanation:
We know that tan theta = cot (90 - theta)
=> cot (90 - 2a) = cot (a - 18)
=> 90 - 2a = a - 18
=> a = 36
Answered by
4
Hello frd ,
Your Solution:-
It is given that tan2A=cot(A−18°)
⇒tan2A=cot(90° −(108° −A))
⇒tan2A=tan(108° −A)
{°•° cot(90° −A)=tan(A)}
⇒2A=108° −A
⇒3A=108°
⇒A=108°/3 =36°
Thanks☺
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