If tan 2A = cot(A+6°), where 2A is an acute angle, find the value of A
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Answered by
29
given : tan2A=cot(A+6°)
to find : A=?
solution : tan2A=cot(A+6°) ( given)
cot(90°-2A) = cot(A+6°)
90°-2A=A+6°
3A=84°
A=28°
to find : A=?
solution : tan2A=cot(A+6°) ( given)
cot(90°-2A) = cot(A+6°)
90°-2A=A+6°
3A=84°
A=28°
Answered by
6
Answer:
Tan 2A=cot(A+6)
cot(90-tetha)=cot(A+6)
90-2A=A+6
3A=84
A=84/3
A=28
Step-by-step explanation:
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