If tan 2A=cot(A+60°),find the value of A,where 2A is an acute angle
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cot ( 90 degree - 2a) -- cot ( a plus 60 degree ) then, 90 - 60 -- a plus 2a so, 30 -- 3a then, a -- 10
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tan 2A = cot ( A + 60° )
cot ( 90° - 2A ) = cot ( A + 60° )
Using trigonometric identity
tan theta = cot ( 90° - theta )
On comparing
90° - 2A = A + 60°
A+ 2A = 90° - 60°
3A = 30°
A = 10°
.
.
мσяє qυєѕтισиѕ
cot ( 90° - 2A ) = cot ( A + 60° )
Using trigonometric identity
tan theta = cot ( 90° - theta )
On comparing
90° - 2A = A + 60°
A+ 2A = 90° - 60°
3A = 30°
A = 10°
.
.
мσяє qυєѕтισиѕ
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