IF TAN 2A=cot(a+60degree) ,find the value of A where 2A is an acute angle
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Answered by
10
We know tan Ф = cot(90-Ф)
So, In R.H.S, tan(90-a+60) = tan(30-a)
Now, tan 2a = tan (30-a)
2a = 30-a
3a=30
a=10....ANS
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Answered by
7
cot(90-2a) = cot(a+60)
90-2a = a+60
30 = 3a
a = 10
therefore 2a = 20
90-2a = a+60
30 = 3a
a = 10
therefore 2a = 20
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