If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A. NCERT Class X Mathematics - Mathematics Chapter _INTRODUCTION TO TRIGONOMETRY
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Cot (90-A)= cot (2a-18)
90-A=2A-18
3A=108
A=36
90-A=2A-18
3A=108
A=36
Answered by
6
Hello friends ☺
Answer:
36°
Step-by-step explanation:
It is given that tan2A=cot(A−18°)
⇒tan2A=cot(90° −(108° −A))
⇒tan2A=tan(108° −A)
{°•° cot(90° −A)=tan(A)}
⇒2A=108° −A
⇒3A=108°
⇒A=108°/3 =36°
Thanks ☺
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