Question

If tan 2A = cot theta ( A - 18 ), where 2A is an acute angle, find the value of A

Answer 1

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$\tan(2A) = \cot(A - 18\degree) \\ \\ \cot(90\degree - 2A) = \cot(A - 18\degree) \\(using \: \tan( \theta) = \cot(90\degree - \theta)) \\ \\ = >90\degree - 2A = A - 18\degree \\ \\ = > - 3A = - 108\degree \\ \\ = > A= 36 \degree$

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Answer 2

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