Question

if tan θ ,2tanθ ₊2 ,3tan θ ₊3 , are in G.P then the value of 7₋5cot θ ÷ 9 ₋4√sec²θ₋1 is

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

the given condition, (2tanθ+2)²=(3tanθ+3)tanθ

⇒4tan²θ+8tanθ+4=3tan²θ+3tanθ

⇒tan²θ+5tanθ+4=0

So, tanθ=−1 or −4, but −1 doesn't satisfy the G.P. condition as two terms become 0.

7−5cotθ/9−4sec²θ−1=7+1.25/9-16=8.25/-7= −33/28

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