if tan 3θ=1 then find the value of sin 2θ
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tan 3 theta = 1
=) tan 3theta = tan 45
=) theta = 45/3 = 15
sin 2theta = 2*15=30
sin 30 = 1/2
=) tan 3theta = tan 45
=) theta = 45/3 = 15
sin 2theta = 2*15=30
sin 30 = 1/2
vanjashivae:
nice
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0
Here I used both trigonometric and inverse trigonometric functions formulae
I hop you get it.
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