Question

If tan=3/4and A+B=90 then find cotB

Answer 1

Cot B = 3/4

Step-by-step explanation:

Given:

Tan A = 3/4

A + B=90

A = 90 - B

Solution:

TanA = 3/4

Tan (90 - B) = 3/4

Cot B = 3/4

Answer 2

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$cot \: B = \frac{3}{4}$

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• $tan \: A \: = \frac{3}{4}$
• $a + b = 90 {}^{o}$

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what is the value of cot B ?

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In ΔABC

∠A+∠B+∠C=180° (Angle sum property of triangle)

Since we are given that ∠A+∠B =90°

So, 90°+∠C=180°

∠C=180°-90°

∠C=90°

So,  ΔABC is a right angled triangle at C

So,

$tan \: θ = \frac{Perpendicular}{Base}$

We are given that  

=>$tan \: A \: = \frac{3}{4}$

So, on comparing

For ∠A

Base = 3

Perpendicular =4

=>$cot \: θ = \frac{Base}{Prependicular}$

=>$cot \: B = \frac{3}{4}$