Question

If tan( + ) = √3 and tan( − ) =

1

√3

; 0° < + ≤ 90°; > , find and .​

Answer 1

Answer:

tan (A + B) = √3 ⇒ A + B = 60° …………..

(i) tan (A – B) = 13√13 ⇒ A – B = 30

° ………… (ii) From Eqn. (i) + Eqn.(ii), we have 2A = 90 ⇒ = 45° From eqn.

(i), A + B = 60° 45° + B = 60°