If tan 3 theta = cot ( theta -18) than find theta
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tan 3θ=cot(θ-18)
cot(90-3θ)=cot(θ-18)
cut cot from both sides
90-3θ=θ-18
90+18=θ+3θ
108=4θ
θ=
θ=27
cot(90-3θ)=cot(θ-18)
cut cot from both sides
90-3θ=θ-18
90+18=θ+3θ
108=4θ
θ=
θ=27
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