Question

If tanθ = 4 then 1/10 ( tan^2 θ + 2 sec^2 θ) = *​

Answer 1

Answer:

5

Step-by-step explanation:

Given that, tanA=4

then, (tan^2A+2sec^A)/10 = [tan^2A+2(1+tan^2A)]/10

= [4^2+2(1+4^2)]/10

= [16+2(1+16)]/10

= [16+2(17)]/10

= [16+34]/10

= 50/10

= 5

hope this will helps you......