Question

If tanθ = 4 then 1/10 ( tan^2 θ + 2 sec^2 θ) = *​

Answer 1

Answer:

answer: 5

Step-by-step explanation:

tan theta =opp/adj

tan theta =4/1

hyp=AC^2=AB^2+BC^2

=AC^2=(4^2)+(1^2)

=AC^2=16+1

=AC=√17

sec theta =hyp/adj

sec theta =√17/1

1/10 ( tan^2 θ + 2 sec^2 θ) = .

1/10 ( (4)^2 +2(√17)^2)

1/10 (16+2(17))

1/10 (16+34)

1/10 (50)

=5