If tan (45°+B) = 2 + root3 , then find tan B and the measure of b.
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Answer:
B=30°
Explanation:
Tan (45°+B)=2+√3
Tan 45°+ Tan B/1-Tan 45° Tan B=2+√3
1 +Tan B/1-1 ×Tan B=2+√3
1+Tan B/ 1-Tan B =2+√3
1+Tan B =(2+√3)(1-Tan B)
1+Tan B=2-2 Tan B +√3-√3 Tan B
3 Tan B+√3 Tan B= 2-1+√3
Tan B(3+√3)=1+√3
Tan B= 1+√3/3+√3
Tan B=1+√3/3(1+√3)
Tan B = 1/√3
[Tan 30°=1/√3]
B=30°
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