if tan 4A×tan5A=1, then A=?
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Answered by
2
Heya !!!
Tan 4A × Tan 5A = 1
Tan ( 4A × 5A) = 1
Tan 20A² = Tan 45°
20A² = 45
A² = 45/20
A = ✓9/4
A = 3/2
★ HOPE IT WILL HELP YOU ★
Tan 4A × Tan 5A = 1
Tan ( 4A × 5A) = 1
Tan 20A² = Tan 45°
20A² = 45
A² = 45/20
A = ✓9/4
A = 3/2
★ HOPE IT WILL HELP YOU ★
JoydipGhosh:
tan4A×tan5A= tan(4A×5A). this step was wrong
Answered by
9
Formulas :
• tanA = sinA / cosA
• sin(A + B) = sinA cosB + cosA sinB
• sin(A - B) = sinA cosB - cosA sinB
• cos(A + B) = cosA cosB - sinA sinB
• cos(A - B) = cosA cosB + sinA sinB
• cos90° = 0
• tan(A + B) = (tanA + tanB) / (1 - tanA tanB)
Solution :
Now, tan4A tan5A = 1
⇒ ( sin4A / cos4A ) ( sin5A / cos5A ) = 1
⇒ sin4A sin5A = cos4A cos5A
⇒ cos4A cos5A - sin4A sin5A = 0
⇒ cos(4A + 5A) = 0
⇒ cos9A = 0
⇒ cos9A = cos90°
⇒ 9A = 90°
⇒ A = 10°
Therefore, A = 10°
• tanA = sinA / cosA
• sin(A + B) = sinA cosB + cosA sinB
• sin(A - B) = sinA cosB - cosA sinB
• cos(A + B) = cosA cosB - sinA sinB
• cos(A - B) = cosA cosB + sinA sinB
• cos90° = 0
• tan(A + B) = (tanA + tanB) / (1 - tanA tanB)
Solution :
Now, tan4A tan5A = 1
⇒ ( sin4A / cos4A ) ( sin5A / cos5A ) = 1
⇒ sin4A sin5A = cos4A cos5A
⇒ cos4A cos5A - sin4A sin5A = 0
⇒ cos(4A + 5A) = 0
⇒ cos9A = 0
⇒ cos9A = cos90°
⇒ 9A = 90°
⇒ A = 10°
Therefore, A = 10°
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