Question

if tan A =1/2 and tan B=1\3, then the value of A + B is ????

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Answer 1

Answer:

tan(a+b)=tanA+tanB/1-tana.tanb

1/2+1/3

/1-1/2×1×3

5/6/5/6=1

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Step-by-step explanation:

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Answer 2

Solution

Given :-

• tan A =1/2 and tan B=1\3,

Find :-

• Value of ( A + B)

Explanation

Using Formula

★ tan ( A + B) = (tan A + tan B )/(1 - tan A tan B)

★ tan 45° = 1

So, keep above Values

==> tan ( A + B) = (1/2 + 1/3)/(1 - 1/2 * 1/3)

==> tan ( A + B) = [(3+2)/2*3] / (6-1)/6

==> tan ( A + B) = 5/6 * 6/5

==> tan ( A + B) = 5/5

==> tan ( A + B) = 1

==>tan ( A + B ) = tan 45°

==> ( A + B) = 45°

Or,

==> tan ( A + B) = π/4

Hence

• Value of ( A + B) = 45° Or, π/4

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