Question

. If tan a =1/2
tan B = 1/3 then (a +B)​

Answer 1

Answer:

please mark as brain list ans

Step-by-step explanation:

tan(a+b)=tanA+tanB/1-tana.tanb

1/2+1/3

/1-1/2×1×3

5/6/5/6=1

Answer 2

GIVEN :–

• tan(A) = ½

• tan(B) = ⅓

TO FIND :–

• tan(A + B) = ?

SOLUTION :–

• We know that –

$\\ \implies \large { \boxed { \bold{ \tan(A + B) = \dfrac{ \tan(A ) + \tan(B) }{1 - \tan(A) \tan(B) }}}}$

• Now put the values –

$\\ \implies \bold{ \tan(A + B) = \dfrac{ \dfrac{1}{2} + \dfrac{1}{3} }{1 - \left(\dfrac{1}{2} \right) \left(\dfrac{1}{3} \right)}}$

$\\ \implies \bold{ \tan(A + B) = \dfrac{ \dfrac{3 + 2}{6}}{1 - \left(\dfrac{1}{6} \right)}}$

$\\ \implies \bold{ \tan(A + B) = \dfrac{ \dfrac{3 + 2}{ \cancel6}}{ \dfrac{6 - 1}{ \cancel6} }}$

$\\ \implies { \bold{ \tan(A + B) = \cancel \dfrac{5}{5} }}$

$\\ \implies \large { \boxed{ \bold{ \tan(A + B) = 1 }}}$