Question

If Tan A= 1/√3 find the sum of 1+sin a/1-sin a​

Answer 1

Step-by-step explanation:

by Pythagorean formula base square +perpendicular square=hypotneuse square

$( \sqrt{3} ) {}^{2} + 1 = (ab) {}^{2} \\ 4 = ab {}^{2} \: \: \: \: \: \: \: \: \: \: ab = \sqrt{2 \\ \\ \\ \\ \\ \\ \\ \\ }$