Math, asked by mb1164227, 19 days ago

if Tan a=1/√3 then sec²a=​

Answers

Answered by divya43955
0

Answer:

2/√3 sec^2a value

Hope it will help you

Answered by rajeevkr0074
0

Answer:

tanθ=31⇒tanθ=tan30∘⇒θ=30∘

cosec2θ+sec2θcosec2θ−sec2θ=cosec230∘+sec230∘cosec230∘−sec230∘

=22+(2/3)222−(2/3)2

=4+4/34−4/3=12+412−4=168=21

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