Math, asked by dash23678, 6 months ago

If tan A =
1/5
tan B=12/13
show that cos 2A = sin 2B

Answers

Answered by ab548
0

Answer:

Step-by-step explanation:

cos2A = \frac{1-tan^{2}A }{1+tan^{2}A }

\frac{1-(1/5)^{2} }{1+(1/5)^{2} }

\frac{25-1}{25+1}

\frac{24}{26}

\frac{12}{13}

sin2B =  \frac{2tanB}{1+tan^{2}B }

\frac{2(12/13)}{1+(12/13)^{2} }

\frac{24/13}{(169+144)/169}

\frac{24}{13} * \frac{169}{313}

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