Question

if tan A=1/5,tanB=2/3 show that cos2A=sin2B
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Answer 1

Answer:

Step-by-step explanation:

cos2A = ( 1 - tan ² A ) / ( 1 + tan ² A )

          = ( 1 - 1 / 7² ) / ( 1 + 1 / 7² )

          =  48/49 ×  49/50 = 24/25

cos2A = 24/25

sin4B = sin 2 ( 2B )

         =  [ 2 tan2B / ( 1 + tan² 2B) ]

         = [ 2 { 2 tanB / ( 1 - tan² B ) } ] / [ 1 + { 2 tanB / ( 1 - tan² B ) } ² ]

         = 4 tanB ( 1 - tan² B) / ( 1+ tan⁴B - 2tan²B + 4tan²B )

         = 4 tanB ( 1 - tan² B) / ( 1+ tan⁴B + 2tan²B )

         = 4 tanB ( 1 - tan² B) / ( 1 + tan² B) ²

         = 4 ( 1/3 ) ( 1 - ¹/₉ ) /  ( 1 + ¹/₉ ) ²

         = 24/ 25

sin4B = 24/ 25

Hence proved cos2A = sin4B ...