if tan A= 1 and tan B =√3 evaluate cos A and Cos B sin A sin B
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tan A=1
tan A=tan45°
A=45°
tan B=√3
tanB=tan60°
B=60°
cosBsinAsinB
cos60°sin45°sin60°
1/2×1/√2×3/√2
3/4
0.75
tan A=tan45°
A=45°
tan B=√3
tanB=tan60°
B=60°
cosBsinAsinB
cos60°sin45°sin60°
1/2×1/√2×3/√2
3/4
0.75
Rshabh:
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