If tan A = 1 and tan B = 3, find the value of the following, cos A cos B - sin A sin B
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tan x = opposite side / adjacent
side
tan x = opposite side / adjacent
side
cos x = adjacent side /
Hypotenuse side
sin x = opposite side /
Hypotenuse side
According to Pythagorean theorem
(AB) ^2= (BC) ^2+ (CA) ^2
tan A = 1
opposite side = 1
adjacent side = 1
Hypotenuse = √2
cos A = 1/√
sin A = 1/√2
tan B = 3
opposite side = 3
adjacent side = 1
Hypotenuse = √10
cos B = 1/√10
sin B = 3/√10
cos A cos B - sin A sin B
= (1/√2) (1/√10) - (1/√2) (3/√10)
= (1/√20) - (3/√20)
= -2/2√5
= -1/√5
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