if tan A = 1 and tan B =√3 then find the value of cos A cosB- sinA× sin B
wardahd1234:
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Hey,
TanA=1
=>TanA=Tan45=>A=45
TanB=√3
=>TanB=Tan60=>B=60.
Now,
cosAcosB-sinAsinB
=cos45cos60-sin45sin60
=1/√2×1/2-1/√2×√3/2
=1/2√2-√3/2√2
=(1-√3)/2√2.
TanA=1
=>TanA=Tan45=>A=45
TanB=√3
=>TanB=Tan60=>B=60.
Now,
cosAcosB-sinAsinB
=cos45cos60-sin45sin60
=1/√2×1/2-1/√2×√3/2
=1/2√2-√3/2√2
=(1-√3)/2√2.
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